document.write( "Question 361774: Can you help with this problem: Show that there is no quadratic equation ax^2 + bx + c = 0 such that a, b, and c are real numbers and 3i and -2i are solutions.\r
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Algebra.Com's Answer #257862 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
If \"3i\" and \"-2i\" are solutions, then \"%28x-3i%29\" and \"%28x%2B2i%29\" are factors of the quadratic equation.
\n" ); document.write( "\"%28x-3i%29%28x%2B2i%29=ax%5E2%2Bbx%2Bc\"
\n" ); document.write( "\"x%5E2%2B2ix-3ix-6i%5E2=ax%5E2%2Bbx%2Bc\"
\n" ); document.write( "\"x%5E2%2B%28-3i%2B2i%29x%2B6=ax%5E2%2Bbx%2Bc\"
\n" ); document.write( "\"x%5E2-ix%2B6=ax%5E2%2Bbx%2Bc\"\r
\n" ); document.write( "\n" ); document.write( "Comparing
\n" ); document.write( "\"a=1\"
\n" ); document.write( "\"b=-i\"
\n" ); document.write( "\"c=6\"
\n" ); document.write( "However a,b, and c are supposed to be real.
\n" ); document.write( "Therefore \"3i\" and \"-2i\" cannot be solutions where a,b, and c are real numbers.
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