document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=361765>Question 361765</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two cars are moving in the same direction pass a point on the road at the same time. Car A is moving with a constant velocity of 15m/s. Car B has a velocity of 5m/s at that instant and is accelerating at the rate of 1m/s^2. \r<BR>\n" );
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document.write( "Useing the formula s=ut+1/2at^2 where s is the distance from the starting point in metres, u is the velocity initially, a is acceleration in m/s^2 and t is the time in seconds. write a relationship between s and t for car A and car B. \r<BR>\n" );
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document.write( "Please help!  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #257849 by </B><A HREF=/tutors/aboutme.mpl?userid=HasanSahin><B>HasanSahin(52)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=HasanSahin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=HasanSahin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=257849\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The relationship is basically like this:\r<BR>\n" );
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document.write( "Let's say the time passed for a certain time: \"t\"\r<BR>\n" );
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document.write( "The car from A point will travel a distance = x1 = 15*t\r<BR>\n" );
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document.write( "The car from B point will travel a distance = x2 = 5*t + (1/2)*1*(t^2)<BR>\n" );
document.write( "u*t is the distance gained by initial velocity and (1/2)*a*t^2 is the distance gained by acceleration.\r<BR>\n" );
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