document.write( "Question 361660: How do you graph linear equations?
\n" ); document.write( " y=2x-6
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Algebra.Com's Answer #257831 by shorty4aboo(8)\"\" \"About 
You can put this solution on YOUR website!
Graphing Linear Equations is a broad topic but lets start with the problem you have given.
\n" ); document.write( "\"y=2x-6\" This problem tells you that your y-intercept is (0,-6) and that your slope is 2. Now with that info you are ready to make the graph. \r
\n" ); document.write( "\n" ); document.write( "1st plot) will be your y-int: (0, -6) put your point at -6 on your y-line of the graph.\r
\n" ); document.write( "\n" ); document.write( "2nd plot) Now to find your next point use your slope which is 2 OR \"2%2F1\". Take your dot at (0,-6) and go up 2 and to the right 1.\r
\n" ); document.write( "\n" ); document.write( "3rd Plot)at (1,-4) \r
\n" ); document.write( "\n" ); document.write( "4th Plot) at (2,-2)\r
\n" ); document.write( "\n" ); document.write( "~*~The slope is easy to decipher: if the NUMERATOR is positive go up the y-axis: if negative go down the y-axis. if the DENOMINATOR is poitive go to the right along the x-axis: if negaitive go left along the x-axis.\r
\n" ); document.write( "\n" ); document.write( "Examples:
\n" ); document.write( "\"3%2F2\" = up 3, right 2
\n" ); document.write( "\"4%2C-7\" = up 4, left 7
\n" ); document.write( "\"-8%2F5\" = down 8, right 5
\n" ); document.write( "\"-2%2F-5\" = down 2, left 5\r
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