document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=361681>Question 361681</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One angle of a triangle measures 6 degrees more than a second angle.  The third angle measures 18 less than twice the sum of the first two angles.  Find the measure of each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #257820 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=257820\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One angle of a triangle measures 6 degrees more than a second angle.  The third angle measures 18 less than twice the sum of the first two angles.  Find the measure of each angle.<BR>\n" );
document.write( "...<BR>\n" );
document.write( "let second angle be x <BR>\n" );
document.write( "first angle = x+6<BR>\n" );
document.write( "third angle = 2(x+x+6)-18= 4x-6<BR>\n" );
document.write( "...<BR>\n" );
document.write( "x+x+6+4x-6=180<BR>\n" );
document.write( "6x=180<BR>\n" );
document.write( "/6<BR>\n" );
document.write( "x=30<BR>\n" );
document.write( "...<BR>\n" );
document.write( "30, 36, 114 degrees<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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