document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=5094>Question 5094</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me with this equation   3/5n-2=1/5n+3<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #2578 by </B><A HREF=/tutors/aboutme.mpl?userid=lotanez><B>lotanez(23)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lotanez><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=2578\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3/5n - 2 = 1/5n + 3<BR>\n" );
document.write( "(get the n values together on one side)<BR>\n" );
document.write( "3/5n - 1/5n - 2 = 1/5n - 1/5n + 3<BR>\n" );
document.write( "3/5n - 1/5n - 2 = 3<BR>\n" );
document.write( "(get the numbers on one side and subtract the fractions)<BR>\n" );
document.write( "2/5n - 2 + 2 = 3 + 2<BR>\n" );
document.write( "2/5n = 5<BR>\n" );
document.write( "(divide out the fraction-flip it over on the other side-reciprocal)<BR>\n" );
document.write( "2/5n / 2/5 = 5 x 5/2<BR>\n" );
document.write( "n = 25/2 <BR>\n" );
document.write( "n = 12.5<BR>\n" );
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