document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=361497>Question 361497</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Trying to help my daughter with Question #54 on page 299 of McDougal Little Algebra 1. <BR>\n" );
document.write( "An In-line skater practices ar a race track. In two trials the skater travles the same distance going from a standstill to his top racing speed. He then travels at his top racing speed for different distances.\r<BR>\n" );
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document.write( "Trial 1, Time at Top Speed 24 seconds, total distance traveled 300 meters.<BR>\n" );
document.write( "Trial 2, Time at Top Speed 29 seconds, Total distance traveled 350 meters.\r<BR>\n" );
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document.write( "A. Model -Write an equation that gives the total distance traveled (in meters) as a function of time (in seconds) at top racing speed.<BR>\n" );
document.write( "B. - Justify -What do the rate of change and initial value in your equation represent? Explain you answer using unit analysis.<BR>\n" );
document.write( "C. Predict - One lap around the race track is 200 meters. The skater starts at a standstill and completes 3 laps. Predict the number of seconds the skater travels at his top racing speed. Explain your method.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #257749 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=257749\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the extra 5 seconds at top speed (29-24) resulted in 50 more meters of travel (350-300)<BR>\n" );
document.write( "___ so the top speed is ___ 50m / 5s or 10 m/s\r<BR>\n" );
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document.write( "10 m/s for 24 s is a distance of 240 m<BR>\n" );
document.write( "___ this means that it takes 60 m (300-240) to get to top speed\r<BR>\n" );
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document.write( "A. d = 10t + 60\r<BR>\n" );
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document.write( "B.  the rate of change represents the top speed , and the initial value represents the speed-up distance<BR>\n" );
document.write( "___ meters = (meters/sec)(sec) + meters\r<BR>\n" );
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document.write( "C.  3 laps is 600m (3 * 200)<BR>\n" );
document.write( "___ 60 m is used for speed-up , so 540m is the distance at top speed<BR>\n" );
document.write( "___ 540m at 10 m/s means 54 sec at top speed </SPAN>\n" );
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