document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=361367>Question 361367</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist has one solution that 34% acid and a second solution that is 58 % acid. How many liters(L) of the 58% acid should be mixed with the 34% to get 80L of a solution that is 40% acid? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #257693 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=257693\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A chemist has one solution that 34% acid and a second solution that is 58 % acid. How many liters(L) of the 58% acid should be mixed with the 34% to get 80L of a solution that is 40% acid?<BR>\n" );
document.write( "---------------------<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "acid + acid = acid<BR>\n" );
document.write( "0.34x + 0.58(80-x) = 0.40*80<BR>\n" );
document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "34x + 58*80 - 58x = 40*80<BR>\n" );
document.write( "-24x = -18*40<BR>\n" );
document.write( "x = (3/4)40<BR>\n" );
document.write( "x = 30 L (amt. of 34% solution needed in the mix)<BR>\n" );
document.write( "---<BR>\n" );
document.write( "80-x = 50 L (amt of 58% solution needed in the mix)<BR>\n" );
document.write( "=======================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );