document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=361286>Question 361286</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello! I am working on quadratic equations this week, in my Algebra class (section 11.4, #4). At the current moment I am stumped and totally confused on this one problem we are required to do. Apart of the requirements for completing the assignment is to show every single step on how I got to my answer. I wasn't sure if anyone could help me, but I thought I would post to see who's the master at these type of equations. Thank you so much in advance for all your help!<BR>\n" );
document.write( "Directions: Solve the equation by making an appropriate substitution. \r<BR>\n" );
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document.write( "4.) \r<BR>\n" );
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document.write( "2x-11&#8730;x- 40=0 \r<BR>\n" );
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document.write( "the answer the book gives is Answer= {64}, but I don't see how I obtain the answer. Any help you can give is GREATLY appreciated.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #257656 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=257656\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x+-+11sqrt%28x%29+-+40+=+0 ALIGN=MIDDLE  ALT=\"2x+-+11sqrt%28x%29+-+40+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "You can sub y for sqrt(x)<BR>\n" );
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document.write( "(2y+5)*(y-8) = 0<BR>\n" );
document.write( "y = 8<BR>\n" );
document.write( "--> x = 64<BR>\n" );
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document.write( "2y+5 = 0<BR>\n" );
document.write( "y = -5/2<BR>\n" );
document.write( "-->x = 25/4 This fits if you use the neg root.\r<BR>\n" );
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