document.write( "Question 5081: Help--how do i figure this one out? Driving me crazy !!!\r
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document.write( "Twenty bearded men gather. Ten have eight-inch beards, six have ten-inch beards, and four have twelve-inch beards. What is the expected length of a randomly selected man from this group?\r
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document.write( "Tried 10/20 x 6/20 x 4/20 =12inches, that doesn't seem right. Please help! \n" );
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Algebra.Com's Answer #2576 by rapaljer(4671)![]() ![]() You can put this solution on YOUR website! This is sort of like a weighted mean. Multiply number of beards time length of beard, sum the products, and divide by the number of men with beards. I get this:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2 at SCC \n" ); document.write( " |