document.write( "Question 5081: Help--how do i figure this one out? Driving me crazy !!!\r
\n" ); document.write( "\n" ); document.write( "Twenty bearded men gather. Ten have eight-inch beards, six have ten-inch beards, and four have twelve-inch beards. What is the expected length of a randomly selected man from this group?\r
\n" ); document.write( "\n" ); document.write( "Tried 10/20 x 6/20 x 4/20 =12inches, that doesn't seem right. Please help!
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Algebra.Com's Answer #2576 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
This is sort of like a weighted mean. Multiply number of beards time length of beard, sum the products, and divide by the number of men with beards. I get this:\r
\n" ); document.write( "\n" ); document.write( "\"%2810%2A8+%2B+6%2A10+%2B+4+%2A+12+%29%2F20\"\r
\n" ); document.write( "\n" ); document.write( "\"%2880%2B60%2B48%29%2F20+\"
\n" ); document.write( "\"188%2F20\" = 9.4 inches\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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