document.write( "Question 360987: My home work ? is a firm produces both am and am/fm car radios. the am radios take 15 hours to produce and the am/fm radios take 20 hours to produce. the number of production hours is limited to 300 hours per week. the plant's capacity is limited to a total of 18 radios per week, and existing orders require that at least 4 am radios and at least 3 am/fm radios br produced per week. Write a system of inequalities reppresenting the situation. In this case let x = am radios and y = am/fm radios. (use LTE for less than or equal to and GTE for greater than or equal to)\r
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document.write( "I'm so lost. \n" );
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Algebra.Com's Answer #257572 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! This same problem came up a few weeks ago. This is what I submitted then. Perhaps it will help you \n" ); document.write( " \n" ); document.write( "A small firm produces both AM and AM/FM car radios. The AM radios take 15 h to produce, and the AM/FM radios take 20 h. The number of production hours is limited to 300 h per week. The plant's capacity is limited to a total of 18 radios per week, and existing orders require that at least 4 AM radios and at least 3 AM/FM radios be produced per week. Write a system of inequalities representing this situation. \n" ); document.write( ": \n" ); document.write( "Let x = number of AM radios; let y = number of AM/FM radios \n" ); document.write( " \n" ); document.write( "The production hour constraint: \n" ); document.write( "15x + 20y =< 300 \n" ); document.write( ": \n" ); document.write( "Plant's capacity constraint: \n" ); document.write( "x + y =< 18 \n" ); document.write( ": \n" ); document.write( "Min AM radio production constraint: \n" ); document.write( "x => 4 \n" ); document.write( "Min AM/FM radio production constraint \n" ); document.write( "y => 3 \n" ); document.write( ": \n" ); document.write( "How about this, did it all make some sense to you? \n" ); document.write( " |