document.write( "Question 360921: If I have a 20% acid solution and a 50% acid solution, how many liters of each do I have to mix to get 600 liters of a 30% solution? \n" ); document.write( "
Algebra.Com's Answer #257520 by Fombitz(32388)\"\" \"About 
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Let A be the amount of 20% acid solution, and B the amount of 50% acid solution.
\n" ); document.write( "1.\"A%2BB=600\"
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\n" ); document.write( ".
\n" ); document.write( "\"20A%2B50B=30%28600%29\"
\n" ); document.write( "2.\"2A%2B5B=1800\"
\n" ); document.write( "Multiply eq. 1 by -2 and add to eq. 2,
\n" ); document.write( "\"-2A-2B%2B2A%2B5B=-1200%2B1800\"
\n" ); document.write( "\"3B=600\"
\n" ); document.write( "\"highlight%28B=200%29\"liters
\n" ); document.write( "Then from eq. 1,
\n" ); document.write( "\"A%2B200=600\"
\n" ); document.write( "\"highlight%28A=400%29\"liters
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