document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=360902>Question 360902</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the dimension of a rectangle whose lenght is three cm less than twice its width, with a perimeter of 33 cm </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #257485 by </B><A HREF=/tutors/aboutme.mpl?userid=IWork4Dessert><B>IWork4Dessert(60)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=IWork4Dessert><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=IWork4Dessert><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=257485\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let width=x and length=2x-3. There are two widths in every rectangle and two lengths in every rectangle. So:\r<BR>\n" );
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document.write( "2x + 2(2x - 3) = 33<BR>\n" );
document.write( "2x + 4x - 6 =33<BR>\n" );
document.write( "6x - 6 = 33<BR>\n" );
document.write( "6x = 27<BR>\n" );
document.write( "x = 4.5\r<BR>\n" );
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document.write( "If you need me to break it down further, I will.\r<BR>\n" );
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document.write( "~IW4D </SPAN>\n" );
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