document.write( "Question 360785: One race car travels at 200 miles per hour and has a 30 minute head start. The second race car travels at 763 milers per hour. At what distance with the faster car catch the slower car? \n" ); document.write( "
Algebra.Com's Answer #257462 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! One race car travels at 200 miles per hour and has a 30 minute head start. \n" ); document.write( " The second race car travels at 763 milers per hour. \n" ); document.write( " At what distance with the faster car catch the slower car? \n" ); document.write( ": \n" ); document.write( "Wow, 763 mph, isn't that about the speed of sound, anyway \n" ); document.write( ": \n" ); document.write( "Let t = time required for it to catch the slower car \n" ); document.write( "then \n" ); document.write( "(t + .5) - travel time of the slower car \n" ); document.write( ": \n" ); document.write( "When this happens the two cars will have traveled the same distance \n" ); document.write( ": \n" ); document.write( "Write a dist equation, dist = speed * time \n" ); document.write( ": \n" ); document.write( "763t = 200(t+.5) \n" ); document.write( "763t = 200t + 100 \n" ); document.write( "763t - 200t = 100 \n" ); document.write( "563t = 100 \n" ); document.write( "t = \n" ); document.write( "t = .1776 hrs \n" ); document.write( ": \n" ); document.write( "Find the dist: \n" ); document.write( ".1776*763 = 135.5 miles, the faster car catches the slower car. \n" ); document.write( ": \n" ); document.write( "confirm this using the slower car \n" ); document.write( "200(.1776+.5) = 135.5 mi also \n" ); document.write( " |