document.write( "Question 360785: One race car travels at 200 miles per hour and has a 30 minute head start. The second race car travels at 763 milers per hour. At what distance with the faster car catch the slower car? \n" ); document.write( "
Algebra.Com's Answer #257462 by ankor@dixie-net.com(22740)\"\" \"About 
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One race car travels at 200 miles per hour and has a 30 minute head start.
\n" ); document.write( " The second race car travels at 763 milers per hour.
\n" ); document.write( " At what distance with the faster car catch the slower car?
\n" ); document.write( ":
\n" ); document.write( "Wow, 763 mph, isn't that about the speed of sound, anyway
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\n" ); document.write( "Let t = time required for it to catch the slower car
\n" ); document.write( "then
\n" ); document.write( "(t + .5) - travel time of the slower car
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\n" ); document.write( "When this happens the two cars will have traveled the same distance
\n" ); document.write( ":
\n" ); document.write( "Write a dist equation, dist = speed * time
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\n" ); document.write( "763t = 200(t+.5)
\n" ); document.write( "763t = 200t + 100
\n" ); document.write( "763t - 200t = 100
\n" ); document.write( "563t = 100
\n" ); document.write( "t = \"100%2F563\"
\n" ); document.write( "t = .1776 hrs
\n" ); document.write( ":
\n" ); document.write( "Find the dist:
\n" ); document.write( ".1776*763 = 135.5 miles, the faster car catches the slower car.
\n" ); document.write( ":
\n" ); document.write( "confirm this using the slower car
\n" ); document.write( "200(.1776+.5) = 135.5 mi also
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