document.write( "Question 360732: saratoga and new york are 180 miles apart. A truck traveled from new york toward saratoga at the rate of 65 miles per hour. Another truck traveled from saratoga toward new york at the rate of 55mph. How many miles did each travel before they met? \n" ); document.write( "

Algebra.Com's Answer #257432 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "*Note distance = r*t or t = d/r
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document.write( "Let x be the diatnace the 65mph truck went.  then (180-x) is distance reamaining for the other.
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document.write( "time being the same for each:***
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document.write( "cross mulitply and solve for x
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document.write( "55x = 65(180mi-x)
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document.write( "55x = 65*180mi -65x 
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document.write( "120x = 11700mi
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document.write( "x = 97.5 mi is the distance of the faster vehicle, the other 82.5 mi\r
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document.write( "checking our answer
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document.write( "97.5/65mph = 82.5/55mphr = 1.5hr (time each traveled befor meeting) \n" );
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