document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=360470>Question 360470</A>: <I><SPAN STYLE=\"word-break: break-all;\"> angle DEF and angle FEG are complementary. m (angle) DEF= (3x-4), and m (angle) FEG= (5x+6) how do I find the measures of both angles? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #257396 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=257396\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> since the angles are complementary, then the sum of both angles must equal 90 degrees.\r<BR>\n" );
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document.write( "you get:\r<BR>\n" );
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document.write( "(5x + 6) + (3x - 4) = 90\r<BR>\n" );
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document.write( "remove parenthese and combine like terms to get:\r<BR>\n" );
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document.write( "8x + 2 = 90\r<BR>\n" );
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document.write( "subtract 2 from both sides of the equation to get:\r<BR>\n" );
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document.write( "8x = 88\r<BR>\n" );
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document.write( "divide both sides of the equation to get:\r<BR>\n" );
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document.write( "x = 11\r<BR>\n" );
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document.write( "if x = 11, then:\r<BR>\n" );
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document.write( "angle 1 = 5x + 6 = 61 degrees\r<BR>\n" );
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document.write( "angle 2 = 3x - 4 = 29 degrees\r<BR>\n" );
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document.write( "sum of the angles is 90 degrees as it should be.\r<BR>\n" );
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document.write( "angle 1 = angle FEG\r<BR>\n" );
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document.write( "angle 2 = angle DEF\r<BR>\n" );
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document.write( "angle FEG = 61 degrees\r<BR>\n" );
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document.write( "angle DEF = 29 degrees\r<BR>\n" );
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document.write( " </SPAN>\n" );
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