document.write( "Question 360670: If sin(x+30)=1/2 (0≤x≤360), then x is equal to?\r
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document.write( "My attempt-\r
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document.write( "sin(x+30)=1/2
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document.write( "sin(angle)=1/2
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document.write( "shift sin 1/2=30\r
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document.write( "x+30=30
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document.write( "x=0\r
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document.write( "so x=0, 180, 360\r
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document.write( "this is a multiple choice question and the answers are-(A) 0,120 OR 360. (B) 0 OR 120 (C) 30 OR 150 (D) 120 OR 360\r
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document.write( "Thanks for any help in advance \n" );
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Algebra.Com's Answer #257387 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! If sin(x+30)=1/2 (0≤x≤360), then x is equal to? \n" ); document.write( "---- \n" ); document.write( "If sin(x+30) = 1/2, x+30 must be 30, or 150, or 390 \n" ); document.write( "---- \n" ); document.write( "If x+30 = 30, x = 0 \n" ); document.write( "If x+30 = 150, x = 120 \n" ); document.write( "If x+30 = 390, x = 360 \n" ); document.write( "Ans: A \n" ); document.write( "--- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |