document.write( "Question 360645: Raju is 19yrs younger than his cousin. After 5 yrs their ages will be the ratio 2:3. Find their ages \n" ); document.write( "
Algebra.Com's Answer #257368 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "*Note: Raju was and always will be 19 year younger than his cousin
\n" ); document.write( "Let x represent his cousin's age, then Raju's age is (x-19)
\n" ); document.write( "write as we read (in 5 years...)***
\n" ); document.write( "\"2%2F3+=+%28x-19%29%2Fx\"
\n" ); document.write( "cross multiply to solve
\n" ); document.write( "2x = 3(x-19)
\n" ); document.write( "solve for x (cousin's age in 5 years)
\n" ); document.write( "2x = 3x - 57
\n" ); document.write( "57 =x (cousin's age in 5 years)\r
\n" ); document.write( "\n" ); document.write( "cousin is now 52 and Raju is 33 (52-19)\r
\n" ); document.write( "\n" ); document.write( "checking our answer
\n" ); document.write( "38/57 = 2/3 \n" ); document.write( "
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