document.write( "Question 360619: train a is traveling at 60 mph and passes the train station at 2:10 pm. Train b is traveling at 80mph and passes the station at 2:22 pm. What time will train b catch up to train a? \n" ); document.write( "

Algebra.Com's Answer #257352 by mananth(16946) $\"\"$ $\"About$

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train a is traveling at 60 mph and passes the train station at 2:10 pm. Train b is traveling at 80mph and passes the station at 2:22 pm. What time will train b catch up to train a?
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\n" ); document.write( "train a - speed = 60 mph --- 2.10pm
\n" ); document.write( "train b -speed = 80mph ----2.22pm
\n" ); document.write( "...
\n" ); document.write( "time difference = 12 minutes
\n" ); document.write( "..
\n" ); document.write( "in 12 minutes train A has traveled 1/5*60 =12 miles
\n" ); document.write( "..
\n" ); document.write( "difference between speeds = 20 mph.
\n" ); document.write( "train b catches up 20 mph.
\n" ); document.write( "to catch up 12 miles it will take
\n" ); document.write( "12/20 = 3/5 hours
\n" ); document.write( "3/5 *60 = 36 minutes
\n" ); document.write( "...
\n" ); document.write( "Add 36 minutes 2.22
\n" ); document.write( "it will catch up at 2.58 pm
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( "

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