document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=360618>Question 360618</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need to know how to write this equation in order to find the answer.<BR>\n" );
document.write( "If I am 48 and my grandson is 2 years old how old, in years, will I be when I am 3 times his age.  I thought that I would just multiply by 3 but the professor said we do not do that to figure out the problem.  I thought that maybe I would be 54 and he would be 16 but then it just did not look right.  So I tried again and what I got today was I would be 60 and he would b3 4.  I am so lost with this problem. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #257344 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=257344\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let me be three times grandson's age after x years<BR>\n" );
document.write( "my age now = 48, grandson's age now =2<BR>\n" );
document.write( "(48+x) / (2+x) = 3<BR>\n" );
document.write( "48+x =3(2+x)<BR>\n" );
document.write( "48+x=6+3x<BR>\n" );
document.write( "48-6=3x-x<BR>\n" );
document.write( "42=2x<BR>\n" );
document.write( "x= 21  -------- 21 years later<BR>\n" );
document.write( "My age = 48+21= 69<BR>\n" );
document.write( "grandson's  age = 2+21= 23<BR>\n" );
document.write( "...<BR>\n" );
document.write( "69=23*3<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );