document.write( "Question 360435: The first national bank of wilson has 650 (population) checking account customers. A recenter sample of 50 (sample) of these customers showed 26 to have a visa card with the bank. Construct the 99 percent confidence interval for the proportion of checking account customers who have a visa card with the bank. \n" ); document.write( "
Algebra.Com's Answer #257338 by robertb(5830)\"\" \"About 
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*The first national bank of Wilson has 650 (population) checking account customers. A recent sample of 50 (sample) of these customers showed 26 to have a visa card with the bank. Construct the 99 percent confidence interval for the proportion of checking account customers who have a visa card with the bank.*\r
\n" ); document.write( "\n" ); document.write( "The confidence interval for a proportion, \"pi\", is
\n" ); document.write( "p ± z σp, where p = 26/50 = 0.52, σp = \"sqrt%28%28%280.52%2A0.48%29%2F50%29%29=0.070654\"(Note that this is just an estimate of the standard error of the proportion, since\"pi\" isn't given in the problem), and z = 2.575.
\n" ); document.write( "Thus 0.52± (2.575)*(0.070654), or (0.338066, 0.701934) \n" ); document.write( "
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