document.write( "Question 360475: The perimeter of a rectangle is 52 inches. The length is 4 less than twice its width. Find the dimensions of the rectangle \n" ); document.write( "
Algebra.Com's Answer #257324 by mananth(16946)\"\" \"About 
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The perimeter of a rectangle is 52 inches. The length is 4 less than twice its width. Find the dimensions of the rectangle
\n" ); document.write( "...
\n" ); document.write( "let width be w
\n" ); document.write( "length = 2w-4
\n" ); document.write( "..
\n" ); document.write( "P= 2*(l+W)
\n" ); document.write( "P=2*(w+2w-4)
\n" ); document.write( "P=2*(3w-4)
\n" ); document.write( "P=6w-8
\n" ); document.write( "..
\n" ); document.write( "6w-8=52
\n" ); document.write( "6w=62+8
\n" ); document.write( "6w=60
\n" ); document.write( "/6
\n" ); document.write( "w= 10 in. the width
\n" ); document.write( "length = 2w-4 = 20-4=16 in.
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\n" ); document.write( "m.ananth@hotmail.ca
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