document.write( "Question 360475: The perimeter of a rectangle is 52 inches. The length is 4 less than twice its width. Find the dimensions of the rectangle \n" ); document.write( "
Algebra.Com's Answer #257324 by mananth(16946) You can put this solution on YOUR website! The perimeter of a rectangle is 52 inches. The length is 4 less than twice its width. Find the dimensions of the rectangle \n" ); document.write( "... \n" ); document.write( "let width be w \n" ); document.write( "length = 2w-4 \n" ); document.write( ".. \n" ); document.write( "P= 2*(l+W) \n" ); document.write( "P=2*(w+2w-4) \n" ); document.write( "P=2*(3w-4) \n" ); document.write( "P=6w-8 \n" ); document.write( ".. \n" ); document.write( "6w-8=52 \n" ); document.write( "6w=62+8 \n" ); document.write( "6w=60 \n" ); document.write( "/6 \n" ); document.write( "w= 10 in. the width \n" ); document.write( "length = 2w-4 = 20-4=16 in. \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |