document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=360559>Question 360559</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Let x be the amount (in hundreds of dollars) a company spends on advertising, and let P be the Profit, where P = 230 + 20x- .5x^2.  What expenditure for advertising results in the maximum profit? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #257322 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=257322\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The equation is quadratic whose graph is a parabola facing down, so it will have a maximum.  The x-value giving the maximum P (profit)value is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-b%2F%282a%29+=+-%2820%2F%282%2A%28-1%2F2%29%29%29+=+20 ALIGN=MIDDLE  ALT=\"-b%2F%282a%29+=+-%2820%2F%282%2A%28-1%2F2%29%29%29+=+20\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Therefore the company has to spend $2,000 to maximize profit. </SPAN>\n" );
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