document.write( "Question 5093: If Sally can paint a house in 4 hours and John can paint the house in 6 hours. How long will it take them to paint the house together? \r
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Algebra.Com's Answer #2573 by rapaljer(4671)![]() ![]() You can put this solution on YOUR website! If Sally can paint the house in 4 hours, then the part she can do in 1 hour is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If John can paint the house in 6 hours, then the part he can do in 1 hour is \n" ); document.write( "\n" ); document.write( "Let x = the number of hours it takes them to paint the house together.\r \n" ); document.write( "\n" ); document.write( "If together they can paint the house in \"x\" hours, then in 1 hour they can paint \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The equation is \"The part Sally can paint in 1 hour + the part that John can paint in 1 hour equals the part they can paint together in 1 hour.\"\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Multiply both sides of the equation by the least common denominator which is \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2 at SCC\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |