document.write( "Question 360579: Solve this equation by using the quadratic form.
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document.write( "x(1/2) + (sqrt 3)x(1/4) - 18 = 0
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document.write( "or
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document.write( "x to the 1/2 power plus sqrt of 3 x to the 1/4 power - 18 = 0.\r
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document.write( "Any help will be greatly appreciated. \n" );
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Algebra.Com's Answer #257294 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! x(1/2) + (sqrt 3)x(1/4) - 18 = 0 \n" ); document.write( "---- \n" ); document.write( "Let w = x^(1/4) \n" ); document.write( "Then w^2 = x^(1/2) \n" ); document.write( "----- \n" ); document.write( "Substitute to get: \n" ); document.write( "w^2 + sqrt(3)w - 18 = 0 \n" ); document.write( "---- \n" ); document.write( "Quadratic Formula: \n" ); document.write( "--- \n" ); document.write( "w = [-sqrt(3) +- sqrt(3-4*-18)]/2 \n" ); document.write( "--- \n" ); document.write( "w = [-sqrt(3) +- sqrt(75)]/2 \n" ); document.write( "--- \n" ); document.write( "w = [-sqrt(3)+-5sqrt(3)]/2 \n" ); document.write( "--- \n" ); document.write( "w = [-3sqrt(3)] or w = 2sqrt(3) \n" ); document.write( "------- \n" ); document.write( "Now, solve for \"x\" using Let w = x^(1/4) \n" ); document.write( "---- \n" ); document.write( "Solve: -3sqrt(3) = x^(1/4) \n" ); document.write( "x = [-3sqrt(3)]^4 = 81*9 = 729 \n" ); document.write( "---- \n" ); document.write( "Solve: 2sqrt(3) = x^(1/4) \n" ); document.write( "x = [2sqrt(3)]^4 = 16*9 = 144 \n" ); document.write( "------ \n" ); document.write( "Check these answers in the original equation: \n" ); document.write( "======== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |