document.write( "Question 360579: Solve this equation by using the quadratic form.
\n" ); document.write( "x(1/2) + (sqrt 3)x(1/4) - 18 = 0
\n" ); document.write( "or
\n" ); document.write( "x to the 1/2 power plus sqrt of 3 x to the 1/4 power - 18 = 0.\r
\n" ); document.write( "\n" ); document.write( "Any help will be greatly appreciated.
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Algebra.Com's Answer #257294 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
x(1/2) + (sqrt 3)x(1/4) - 18 = 0
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\n" ); document.write( "Let w = x^(1/4)
\n" ); document.write( "Then w^2 = x^(1/2)
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\n" ); document.write( "Substitute to get:
\n" ); document.write( "w^2 + sqrt(3)w - 18 = 0
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\n" ); document.write( "Quadratic Formula:
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\n" ); document.write( "w = [-sqrt(3) +- sqrt(3-4*-18)]/2
\n" ); document.write( "---
\n" ); document.write( "w = [-sqrt(3) +- sqrt(75)]/2
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\n" ); document.write( "w = [-sqrt(3)+-5sqrt(3)]/2
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\n" ); document.write( "w = [-3sqrt(3)] or w = 2sqrt(3)
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\n" ); document.write( "Now, solve for \"x\" using Let w = x^(1/4)
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\n" ); document.write( "Solve: -3sqrt(3) = x^(1/4)
\n" ); document.write( "x = [-3sqrt(3)]^4 = 81*9 = 729
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\n" ); document.write( "Solve: 2sqrt(3) = x^(1/4)
\n" ); document.write( "x = [2sqrt(3)]^4 = 16*9 = 144
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\n" ); document.write( "Check these answers in the original equation:
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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