document.write( "Question 360584: Kevin takes pictures for weddings and special occasions. He charges a certain amount for the event and then charges so much for each picture he takes. For stacy's wedding he charged $600 and took 200 pictures. For shelly's wedding he charged $712.50 and took 275 pictures. How much does kevin charge per picture?
\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #257281 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"e\"$ = the amount he charges per event
\n" ); document.write( "Let $\"p\"$ = the amount he charges per picture
\n" ); document.write( "given:
\n" ); document.write( "For Stacy's wedding:
\n" ); document.write( "(1) $\"60000+=+e+%2B+200p\"$ (in cents)
\n" ); document.write( "For Shelly's wedding:
\n" ); document.write( "(2) $\"71250+=+e+%2B+275p\"$ (in cents)
\n" ); document.write( "Subtract equation (1) from (2)
\n" ); document.write( " $\"71250+=+e+%2B+275p\"$
\n" ); document.write( " $\"-60000+=+-e+-+200p\"$
\n" ); document.write( " $\"11250+=+75p\"$
\n" ); document.write( " $\"p+=+150\"$
\n" ); document.write( "Keven charges $\"150\"$ cents, or $1.50 per picture
\n" ); document.write( "check answer:
\n" ); document.write( "(1) $\"60000+=+e+%2B+200p\"$
\n" ); document.write( " $\"60000+=+e+%2B+200%2A150\"$
\n" ); document.write( " $\"60000+=+e+%2B+30000\"$
\n" ); document.write( " $\"e+=+60000+-+30000\"$
\n" ); document.write( " $\"e+=+30000\"$
\n" ); document.write( "and
\n" ); document.write( "(2) $\"71250+=+e+%2B+275p\"$
\n" ); document.write( " $\"71250+=+30000+%2B+275p\"$
\n" ); document.write( " $\"275p+=+41250\"$
\n" ); document.write( " $\"p+=+150\"$
\n" ); document.write( "OK
\n" ); document.write( " \n" ); document.write( "

\n" );