document.write( "Question 360575: Find the amount of a 6% acid solution and the amount of a 14% acid solution that should be combined to prepare 50cc of a 12% solution. \r
\n" ); document.write( "\n" ); document.write( "I believe the equation is set up this way:\r
\n" ); document.write( "\n" ); document.write( "1st 6% = .06x
\n" ); document.write( "2nd 14% = .14y
\n" ); document.write( "mix 12% = .12(50)\r
\n" ); document.write( "\n" ); document.write( "x + y = 50
\n" ); document.write( ".06x + .14y = 6
\n" ); document.write( "Then subtract .14y from both sides, then multiply both by 100? \r
\n" ); document.write( "\n" ); document.write( "Am I on the right track, because I am way off on the correct answer. \r
\n" ); document.write( "\n" ); document.write( "Thanks in advance! \n" ); document.write( "
Algebra.Com's Answer #257275 by Alan3354(69443)\"\" \"About 
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Find the amount of a 6% acid solution and the amount of a 14% acid solution that should be combined to prepare 50cc of a 12% solution.
\n" ); document.write( "I believe the equation is set up this way:
\n" ); document.write( "x = amount of 6%
\n" ); document.write( "y = amount of 14%
\n" ); document.write( "1st 6% = .06x ( = amount of acid in x cc's of 6%)
\n" ); document.write( "2nd 14% = .14y ( = amount of acid in y cc's of 14%)
\n" ); document.write( "mix 12% = .12(50)
\n" ); document.write( "x + y = 50
\n" ); document.write( "0.06x + 0.14y = 0.12*50\r
\n" ); document.write( "\n" ); document.write( ".06x + .14y = 6 This is not right.
\n" ); document.write( "Then subtract .14y from both sides, then multiply both by 100?
\n" ); document.write( "Am I on the right track, because I am way off on the correct answer.
\n" ); document.write( "-----------------
\n" ); document.write( "Solve these 2 eqns
\n" ); document.write( "x + y = 50
\n" ); document.write( "0.06x + 0.14y = 0.12*50
\n" ); document.write( " \n" ); document.write( "
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