document.write( "Question 360485: 2^(x)-2^(x-1)=32 x=? answ is x=6 but i want to know the solution? \n" ); document.write( "
Algebra.Com's Answer #257271 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
\"2%5E%28x%29-2%5E%28x-1%29=32\"
\n" ); document.write( "same as
\n" ); document.write( "\"2%5E%28x%29-%282%5E%28x%29%2F2%5E1%29=32\"
\n" ); document.write( "or just
\n" ); document.write( "\"2%5E%28x%29-%282%5E%28x%29%2F2%29=32\"
\n" ); document.write( "multiply by 2 to get rid of the denominator, results:
\n" ); document.write( "\"2%282%5Ex%29-2%5Ex=2%2832%29\"
\n" ); document.write( "now we have like terms so we can just subtract, results:
\n" ); document.write( "\"2%5Ex+=+64\"
\n" ); document.write( "therefore
\n" ); document.write( "x = 6
\n" ); document.write( "
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