document.write( "Question 360513: a boat crew rowed 16 miles downstream with the current in 2 hours . the return trip upstream against the current covered the same distance but took 4 hours find the crews rowing rate in still water of the current.\r
\n" ); document.write( "\n" ); document.write( "the crew rowing rate in still water is_________miles per hour
\n" ); document.write( "the rate of the current is_________miles per hour
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Algebra.Com's Answer #257262 by checkley77(12844)\"\" \"About 
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D=RT
\n" ); document.write( "16=R*2
\n" ); document.write( "R=16/2
\n" ); document.write( "R=8 MPH. WITH THE CURRENT.
\n" ); document.write( "16=R*4
\n" ); document.write( "R=16/4
\n" ); document.write( "R=4 MPH AGAINST THE CURRENT.
\n" ); document.write( "(8-4)/2=4/2=2 MPH IS THE RATE OF THE CURRENT.
\n" ); document.write( "8-2=6 MPH RATE OF THE BOAT IN STILL WATER.
\n" ); document.write( "4+2=6 MPH DITTO.
\n" ); document.write( "PROOF:
\n" ); document.write( "16=(6+2)*2
\n" ); document.write( "16=8*2
\n" ); document.write( "16=16
\n" ); document.write( "16=(6-2)4
\n" ); document.write( "16=4*4
\n" ); document.write( "16=16
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