document.write( "Question 360513: a boat crew rowed 16 miles downstream with the current in 2 hours . the return trip upstream against the current covered the same distance but took 4 hours find the crews rowing rate in still water of the current.\r
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document.write( "the crew rowing rate in still water is_________miles per hour
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document.write( "the rate of the current is_________miles per hour \n" );
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Algebra.Com's Answer #257262 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "16=R*2 \n" ); document.write( "R=16/2 \n" ); document.write( "R=8 MPH. WITH THE CURRENT. \n" ); document.write( "16=R*4 \n" ); document.write( "R=16/4 \n" ); document.write( "R=4 MPH AGAINST THE CURRENT. \n" ); document.write( "(8-4)/2=4/2=2 MPH IS THE RATE OF THE CURRENT. \n" ); document.write( "8-2=6 MPH RATE OF THE BOAT IN STILL WATER. \n" ); document.write( "4+2=6 MPH DITTO. \n" ); document.write( "PROOF: \n" ); document.write( "16=(6+2)*2 \n" ); document.write( "16=8*2 \n" ); document.write( "16=16 \n" ); document.write( "16=(6-2)4 \n" ); document.write( "16=4*4 \n" ); document.write( "16=16 \n" ); document.write( " \n" ); document.write( " |