document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=360566>Question 360566</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1.   logx 8=3<BR>\n" );
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document.write( "2.log 10(2x-4)  _ log 10(x+2) =1<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #257255 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=257255\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1. logx 8=3<BR>\n" );
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document.write( "x^3 = 8<BR>\n" );
document.write( "x = 2<BR>\n" );
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document.write( "2.log 10(2x-4) - log 10(x+2) =1<BR>\n" );
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document.write( "log10[(2x-4)/(x+2)] = 1<BR>\n" );
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document.write( "[(2x-4)/(x+2)] = 10<BR>\n" );
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document.write( "2x-4 = 10x+20<BR>\n" );
document.write( "8x = -24<BR>\n" );
document.write( "x = -3<BR>\n" );
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document.write( "But x cannot be -3 in the original equation<BR>\n" );
document.write( "because you cannot have the log of a negative<BR>\n" );
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document.write( "No solution:<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "stan H.\r<BR>\n" );
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