document.write( "Question 360530: I'm trying to understand the formula or how to solve these problems.\r
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document.write( "3y to the 2nd power + y-4=0\r
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document.write( "2a to the 2nd power =11a-12\r
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document.write( "3j(j-2)=2(2-j) \n" );
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Algebra.Com's Answer #257222 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 3y^2 + y - 4=0 \n" ); document.write( "Factor: \n" ); document.write( "(3y+4)(y-1) = 0 \n" ); document.write( "--- \n" ); document.write( "y = [-4/3] or y = 1 \n" ); document.write( "================================== \n" ); document.write( " \n" ); document.write( "2a^2 = 11a - 12 \n" ); document.write( "--- \n" ); document.write( "2a^2 - 11a + 12 = 0 \n" ); document.write( "2a^2-8a-3a+12 = 0 \n" ); document.write( "2a(a-4)-3(a-4) = 0 \n" ); document.write( "(a-4)(2a-3) = 0 \n" ); document.write( "a = 4 or a = 3/2 \n" ); document.write( "================================= \r \n" ); document.write( "\n" ); document.write( "3j(j-2)=2(2-j)\r \n" ); document.write( "\n" ); document.write( "3j(j-2) + 2(j-2) = 0 \n" ); document.write( "--- \n" ); document.write( "(j-2)(3j+2) = 0 \n" ); document.write( "--- \n" ); document.write( "j = 2 or j = -2/3 \n" ); document.write( "======================= \n" ); document.write( "Cheers, \n" ); document.write( "St \n" ); document.write( " |