document.write( "Question 360530: I'm trying to understand the formula or how to solve these problems.\r
\n" ); document.write( "\n" ); document.write( "3y to the 2nd power + y-4=0\r
\n" ); document.write( "\n" ); document.write( "2a to the 2nd power =11a-12\r
\n" ); document.write( "\n" ); document.write( "3j(j-2)=2(2-j)
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Algebra.Com's Answer #257222 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
3y^2 + y - 4=0
\n" ); document.write( "Factor:
\n" ); document.write( "(3y+4)(y-1) = 0
\n" ); document.write( "---
\n" ); document.write( "y = [-4/3] or y = 1
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\n" ); document.write( "2a^2 = 11a - 12
\n" ); document.write( "---
\n" ); document.write( "2a^2 - 11a + 12 = 0
\n" ); document.write( "2a^2-8a-3a+12 = 0
\n" ); document.write( "2a(a-4)-3(a-4) = 0
\n" ); document.write( "(a-4)(2a-3) = 0
\n" ); document.write( "a = 4 or a = 3/2
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\n" ); document.write( "\n" ); document.write( "3j(j-2)=2(2-j)\r
\n" ); document.write( "\n" ); document.write( "3j(j-2) + 2(j-2) = 0
\n" ); document.write( "---
\n" ); document.write( "(j-2)(3j+2) = 0
\n" ); document.write( "---
\n" ); document.write( "j = 2 or j = -2/3
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\n" ); document.write( "Cheers,
\n" ); document.write( "St
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