document.write( "Question 360469: twice the greater of two consecutive odd integers is less than three times the lesser number. find the integers. \n" ); document.write( "
Algebra.Com's Answer #257194 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi
\n" ); document.write( "*Note: consecutive odd integers differ by 2. Let x be the smaller, (x+2) would be the larger
\n" ); document.write( "write as we read***
\n" ); document.write( "2(x +2) < 3x
\n" ); document.write( "2x + 4 < 3x
\n" ); document.write( "4 < x
\n" ); document.write( "Odd consecutive integers where the first odd integer is greater than 4 would work.
\n" ); document.write( "for ex 5 & 7, 7 & 9, 9 & 11 etc \n" ); document.write( "
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