document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=360423>Question 360423</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how to solve for x, when ln(-9x+7)=3? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #257178 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=257178\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ln(-9x+7)=3<BR>\n" );
document.write( "-9x+7 = e^3<BR>\n" );
document.write( "-9x = e^3 - 7<BR>\n" );
document.write( "9x = 7 - e^3<BR>\n" );
document.write( "x = (7 - e^3)/9<BR>\n" );
document.write( "x = (-13.0855)/9<BR>\n" );
document.write( "x = -1.454 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );