document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=360383>Question 360383</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have been in my job for 1/4 of my life. I asked myself how long it would be until I had been in my job for 1/3 of my life.  \r<BR>\n" );
document.write( "\n" );
document.write( "I don't know how to set this up.  I have asked this question before and got the answer of 1/12. I don't think this is correct because it is not taking into account the time added to your life.  <BR>\n" );
document.write( "EX: been working for 6 out of 24 total years.  1/12 of 24 is 2, and 8/24 is 1/3 but in the problem we need to add the 1/12 to your age also.  8/26 is not 1/3.  Could someone please help me and explain how to set this problem up so that the years of work and your age increase by the same amount.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #257169 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=257169\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I have been in my job for 1/4 of my life. I asked myself how long it would be until I had been in my job for 1/3 of my life. <BR>\n" );
document.write( "I don't know how to set this up. I have asked this question before and got the answer of 1/12. I don't think this is correct because it is not taking into account the time added to your life. <BR>\n" );
document.write( "EX: been working for 6 out of 24 total years. 1/12 of 24 is 2, and 8/24 is 1/3 but in the problem we need to add the 1/12 to your age also. 8/26 is not 1/3. Could someone please help me and explain how to set this problem up so that the years of work and your age increase by the same amount.<BR>\n" );
document.write( "--------------<BR>\n" );
document.write( "j = years at job<BR>\n" );
document.write( "a = age<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "j/a = 1/4<BR>\n" );
document.write( "(j+x)/(a+x) = 1/3<BR>\n" );
document.write( "---------<BR>\n" );
document.write( "a = 4j<BR>\n" );
document.write( "(j+x)/(4j+x) = 1/3<BR>\n" );
document.write( "3(j+x) = 4j+x<BR>\n" );
document.write( "3j+3x = 4j+x<BR>\n" );
document.write( "2x = j<BR>\n" );
document.write( "x = j/2<BR>\n" );
document.write( "--------<BR>\n" );
document.write( "For your example j = 6, x = 3<BR>\n" );
document.write( "6/24 = 1/4<BR>\n" );
document.write( "9/27 = 1/3<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );