document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=360345>Question 360345</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jim and John drive from point A to point B  separate cars. Jim leaves at 6 am and arrives at 4 pm. John leaves at 10 am and arrives at 3 pm. Assume both men drive at constant speeds. Find when John catches up with Jim. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #257148 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=257148\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Jim and John drive from point A to point B  separate cars. Jim leaves at 6 am and arrives at 4 pm. John leaves at 10 am and arrives at 3 pm. Assume both men drive at constant speeds. Find when John catches up with Jim.<BR>\n" );
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document.write( "m = Jim's speed<BR>\n" );
document.write( "n = John's speed<BR>\n" );
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document.write( "d = rt<BR>\n" );
document.write( "To go the total distance:<BR>\n" );
document.write( "d = m*10 --> m = d/10<BR>\n" );
document.write( "d = n*5 --> n = d/5<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "Jim starts at 0600, t = 0<BR>\n" );
document.write( "At some time t:<BR>\n" );
document.write( "m*t = n*(t-4)<BR>\n" );
document.write( "(d/10)t = (d/5)*(t-4)<BR>\n" );
document.write( "d cancels<BR>\n" );
document.write( "t/10 = (t-4)/5<BR>\n" );
document.write( "t = 2(t-4)<BR>\n" );
document.write( "t = 2t - 8<BR>\n" );
document.write( "t = 8 hours<BR>\n" );
document.write( "0600 + 8 = 1400 or 2 PM<BR>\n" );
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document.write( "Interesting problem.<BR>\n" );
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document.write( "Another approach:<BR>\n" );
document.write( "John's speed is 2x Jim's speed.  Since John arrived 1 hour before Jim going 2x as fast, John covered the same distance in his last hour that Jim covered in 2 hours.<BR>\n" );
document.write( "--> They were at the same point 1 hour before John's arrival and 2 hours before Jim's arrival.<BR>\n" );
document.write( "--> 3PM - 1 hour = 4PM - 2 hours<BR>\n" );
document.write( "= 2PM </SPAN>\n" );
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