document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=360314>Question 360314</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two complementary angles are in the ratio of 2:3, find the measure of the complementary angle what does this mean? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #257119 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=257119\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two complementary angles are in the ratio of 2:3, find the measure of the complementary angle what does this mean?<BR>\n" );
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document.write( "Let x = measure of one angle<BR>\n" );
document.write( "then because they're complementary<BR>\n" );
document.write( "90-x = measure of second angle<BR>\n" );
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document.write( "x/(90-x) = 2/3<BR>\n" );
document.write( "cross multiply:<BR>\n" );
document.write( "3x = 2(90-x)<BR>\n" );
document.write( "3x = 180-2x<BR>\n" );
document.write( "5x = 180<BR>\n" );
document.write( "x = 36 degrees (first angle)<BR>\n" );
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document.write( "Second angle:<BR>\n" );
document.write( "90-x = 90-36 = 54 degrees<BR>\n" );
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