document.write( "Question 360273: The present age of a man is 3 times that of his son. 6 years ago, the age of the man was 4 times that of his son. Find the ratio of their ages 6 years later. \n" ); document.write( "
Algebra.Com's Answer #257085 by mananth(16946)\"\" \"About 
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The present age of a man is 3 times that of his son. 6 years ago, the age of the man was 4 times that of his son. Find the ratio of their ages 6 years later.
\n" ); document.write( "son = x
\n" ); document.write( "father = 3x
\n" ); document.write( "..
\n" ); document.write( "6 years ago
\n" ); document.write( "son = x-6
\n" ); document.write( "father = 3x-6
\n" ); document.write( "..
\n" ); document.write( "3x-6=4(x-6)
\n" ); document.write( "3x-6=4x-24
\n" ); document.write( "-x=-18
\n" ); document.write( "x=18 son's age
\n" ); document.write( "father's age = 54 years
\n" ); document.write( "
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