document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=360260>Question 360260</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I can't remember how to do these? I know it's rate times time = distance, but I come up with 54mph, is this right?\r<BR>\n" );
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document.write( "A twin-engined aircraft can fly 648 miles from city A to B in 3 hours with the wind and make the return trip in 6 hours against the wind. What is the speed of the wind? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #257077 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=257077\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A twin-engined aircraft can fly 648 miles from city A to B in 3 hours with the wind and make the return trip in 6 hours against the wind. What is the speed of the wind?<BR>\n" );
document.write( "...<BR>\n" );
document.write( "distance = 648<BR>\n" );
document.write( "time = 3 hours<BR>\n" );
document.write( "speed with wind = 648/3 = 216 mph<BR>\n" );
document.write( "speed of wind = x<BR>\n" );
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document.write( "against wind speed = 648/6 = 108 mph\r<BR>\n" );
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document.write( ",..<BR>\n" );
document.write( "216-x=x+108<BR>\n" );
document.write( "216-108=2x<BR>\n" );
document.write( "108=2x<BR>\n" );
document.write( "x= 58 mph wind rate<BR>\n" );
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document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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