document.write( "Question 360260: I can't remember how to do these? I know it's rate times time = distance, but I come up with 54mph, is this right?\r
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document.write( "A twin-engined aircraft can fly 648 miles from city A to B in 3 hours with the wind and make the return trip in 6 hours against the wind. What is the speed of the wind? \n" );
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Algebra.Com's Answer #257076 by robertb(5830)![]() ![]() You can put this solution on YOUR website! let p = speed of the wind in still air, w = speed of the wind.\r \n" ); document.write( "\n" ); document.write( "Then \n" ); document.write( " \n" ); document.write( "Adding corresponding sides of the equations, we get \n" ); document.write( "2p = 324, \n" ); document.write( "p = 162, and w = 216-162 = 54. \n" ); document.write( "The plane goes 162 mph, the wind 54 mph. \n" ); document.write( " \n" ); document.write( " |