document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=360216>Question 360216</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm trying to figure out the answer to the problem.  4^(-2/3)\r<BR>\n" );
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document.write( "Here are my mechanics, 4^(-2/3) = (invert a neg. exponent to make it possitive)4^(3/2)= 2 &#8730;43 = 2 &#8730;64 = 8 ( Using the principle that when you have a fractional exponent use the following rule:  X^(a/b)= b&#8730;Xa) Is this answer correct, or have I made an error.  Thank you in advance. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #257053 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=257053\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4^(-2/3)<BR>\n" );
document.write( "=1/4^(2/3)<BR>\n" );
document.write( "=1/16(1/3)<BR>\n" );
document.write( "=1/(2*2^(1/3))<BR>\n" );
document.write( "=1/(2*2^(1/3)) * 2^(2/3)/2^(2/3) Rationalizing the denominator.<BR>\n" );
document.write( "=2^(2/3)/4<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
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