document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=360109>Question 360109</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much pure antifreeze must be added to 12 L of a 40% solution to obtain a 60% solution. (Remember that pure antifreeze is 100% = 1.) What is the correct question to solve this problem?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #257045 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=257045\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How much pure antifreeze must be added to 12 L of a 40% solution to obtain a 60% solution. (Remember that pure antifreeze is 100% = 1.) What is the correct question to solve this problem?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "active + active = active<BR>\n" );
document.write( "0.40*12 + 1.00x = 0.60(12+x)<BR>\n" );
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document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "40*12 + 100x = 60*12 + 60x<BR>\n" );
document.write( "40x = 20*12<BR>\n" );
document.write( "x = 6 L (amt. of 100% antifreeze that must be added to the mixture)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. \r<BR>\n" );
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