document.write( "Question 360167: A rectangular garden is to be surrounded by a walkway of constant width. The garden’s dimensions are 20 ft by 28 ft. The total area, garden plus walkway, is to be 1,100 ft2. What must be the width of the walkway? \n" ); document.write( "
Algebra.Com's Answer #257041 by checkley77(12844)\"\" \"About 
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(20+2X)(28+2X)=1,100
\n" ); document.write( "560+56X+40X+4X^2=1,100
\n" ); document.write( "4X^2+96X+560-1,100=0
\n" ); document.write( "4X^2+96X-540=0
\n" ); document.write( "4(X^2+24X-135)=0
\n" ); document.write( "\"X+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "X=(-24+-SQRT[2462-4*1*-135])/2*1
\n" ); document.write( "X=(-24+-SQRT[576+540])/2
\n" ); document.write( "X=(-24+-SQRT1,116)/2
\n" ); document.write( "X=(-24+-33.4)/2
\n" ); document.write( "X=(-24+33.4)/2
\n" ); document.write( "X=9.4/2
\n" ); document.write( "X=4.7 FT. IS THE WIDTH OF THE WALKWAY.
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