document.write( "Question 360172: how much pure antifreeze must be added to 12 gallons of 20% antifreeze to make a 80% antifreeze solution \n" ); document.write( "

Algebra.Com's Answer #256991 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "Let x represent the amount of pure antifreeze that must be added 
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document.write( "*Note: the pure antifreeze would be an 100% 'solution' of antifreeze
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document.write( "write as we read***
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document.write( ".20*12gal + 1*x = .80(12gal + x)
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document.write( "solve for x
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document.write( ".2x = .60*12gal
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document.write( "x = 36 gal of antifreeze needs to be added\r
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document.write( "checking our answer 2.4 + 36 = 38.4 \n" );
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