document.write( "Question 360166: Find three consecutive odd integers such that the sum of the first, twice the second, and three times the third is 70? \n" ); document.write( "

Algebra.Com's Answer #256982 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "*Note: consecutive odd integers differ by 2
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document.write( "Le x represent the first odd integer.  
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document.write( "Then (x+2) and(x+4) would be the next two consecutive odd integers\r
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document.write( "write as we read
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document.write( "x + 2(x+2) + 3(x+4) = 70
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document.write( "Solving for x
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document.write( "6x +4 + 12 = 70
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document.write( "6x = 54
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document.write( "x = 9
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document.write( "three consecutive odd integers are 9, 11, 13
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document.write( "checking our answer
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document.write( "9 + 22 + 39 = 70 \n" );
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