document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=360112>Question 360112</A>: <I><SPAN STYLE=\"word-break: break-all;\"> okay Mrs. Brook lacks 7 years from being five times as old as her son. Six years from now she will lack 3 years from being three times as old as her son is then. Find each of the numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #256959 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=256959\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Mrs. Brook lacks 7 years from being five times as old as her son. Six years from now she will lack 3 years from being three times as old as her son is then. Find each of the numbers.<BR>\n" );
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document.write( "Equations:<BR>\n" );
document.write( "b = 5s-7<BR>\n" );
document.write( "(b+6) = 3(s+6)-3<BR>\n" );
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document.write( "Substitute for \"b\" and solve for \"s\":<BR>\n" );
document.write( "5s-7+6 = 3s+18-3<BR>\n" );
document.write( "2s = 16<BR>\n" );
document.write( "s = 8 yrs old (her son's age now)<BR>\n" );
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document.write( "Since b = 5s-7, b = 5*8-7 = 33 yrs old (Mrs. Brook's age now)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( " </SPAN>\n" );
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