document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=360077>Question 360077</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve for y using the addition principle: = -1/8 + y = -3/4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #256938 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=256938\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -1/8 + y = -3/4<BR>\n" );
document.write( "add 1/8<BR>\n" );
document.write( "-1/8 +1/8 +y=-3/4 +1/8<BR>\n" );
document.write( "y=-3/4 +1/8<BR>\n" );
document.write( "LCM = 8<BR>\n" );
document.write( "y= (-6+1)/8<BR>\n" );
document.write( "y=-5/8<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );