document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=360084>Question 360084</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How would you solve: -4c - 11 = 4c + 21 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #256922 by </B><A HREF=/tutors/aboutme.mpl?userid=Jk22><B>Jk22(389)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Jk22><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Jk22><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=256922\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -4c - 11 = 4c + 21 | +4c on both side does not change the equation (since reported on the same side, will give _ +4c-4c=0 added)<BR>\n" );
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document.write( "-11 = 8c + 21    | -21<BR>\n" );
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document.write( "-11 - 21 = 8c<BR>\n" );
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document.write( "-32 = 8c  | divide by 8 on both side<BR>\n" );
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document.write( "-4 = c </SPAN>\n" );
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