document.write( "Question 360006: Sue is traveling 50 miles to an appointment she has to be to in 1 hour. After the first 30 miles she realizes she isn't going to make it and increases her speed by 15mph to get there on time. What was her speed for the first 30 miles? \n" ); document.write( "
Algebra.Com's Answer #256912 by mananth(16949) You can put this solution on YOUR website! Sue is traveling 50 miles to an appointment she has to be to in 1 hour. After the first 30 miles she realizes she isn't going to make it and increases her speed by 15mph to get there on time. What was her speed for the first 30 miles?\r \n" ); document.write( "\n" ); document.write( "let her speed for 30 miles be xmph \n" ); document.write( "time taken = 30/x\r \n" ); document.write( "\n" ); document.write( "speed increased to x+15 mph \n" ); document.write( "time taken = 20/(x+5) \n" ); document.write( ".. \n" ); document.write( "(30/x)+20/(x+5)=1 \n" ); document.write( "30(x+5)+20x / x(x+5)=1 \n" ); document.write( "30x+150+20x = x^2+5x \n" ); document.write( "50x+150-x^2-5x=0 \n" ); document.write( "-x^2+45x+150=0 \n" ); document.write( "x^2-45x-150=0 \n" ); document.write( "solve using quadratic formula\r \n" ); document.write( "\n" ); document.write( "discriminant = 2625 \n" ); document.write( "x1= (45+sqrt(2625))/2 \n" ); document.write( "x1=48.11 mph \n" ); document.write( "x2 will be negative so ignore\r \n" ); document.write( "\n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |