document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37585>Question 37585</A>: <I><SPAN STYLE=\"word-break: break-all;\"> PQRS in a parallelogram,Q and S are joined to any point M on the diagonal PR of the parallelogram.Prove that area of the triangle PQM=area of triangle PSM </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #25685 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=25685\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> PQRS in a parallelogram,Q and S are joined to any point M on the diagonal PR of the parallelogram.Prove that area of the triangle PQM=area of triangle PSM<BR>\n" );
document.write( "IN THE DIAGRAM ,DRAW ST FROM S AND QV FROM Q ,PERPENDICULAR TO PR THE DIAGONAL ,MEETING IT AT T AND V RESPECTIVELY.<BR>\n" );
document.write( "NOW PARALLELOGRAM PQRS IS DIVIDED IN TO 2 EQUAL PARTS BY DIAGONAL PR(EASILY PROVED BY SSS ..PQ=RS,PR=PR AND PS=QR)<BR>\n" );
document.write( "SO AREA OF TRIANGLE PRS=AREA OF TRIANGLE PQR..<BR>\n" );
document.write( "THEY HAVE SAME BASE PR.<BR>\n" );
document.write( "HENCE THEIR ALTITUDES TO THAT SAME BASE ARE EQUAL<BR>\n" );
document.write( "THAT IS ST=QV<BR>\n" );
document.write( "NOW TRIANGLES PQM AND PSM HAVE SAME BASE PM.<BR>\n" );
document.write( "THEIR ATITUDES TO THAT BASE ST AND QV ARE EQUAL.HENCE AREA OF TRIANGLE PQM=AREA OF TRIANGLE PSM </SPAN>\n" );
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