document.write( "Question 40285: The length of a picture is 1 inch less than twice its width. The frame around the picture has a uniform width of 2 inches and an area of 96 square inches. What are the dimensions of the picture? \n" ); document.write( "
Algebra.Com's Answer #25684 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The length of a picture is 1 inch less than twice its width. The frame around the picture has a uniform width of 2 inches and an area of 96 square inches. What are the dimensions of the picture?\r \n" ); document.write( "\n" ); document.write( "OUTSIDE FRAME DATA: \n" ); document.write( "Let the width be \"x\" \n" ); document.write( "Then the length is \"2x-1\" inches.\r \n" ); document.write( "\n" ); document.write( "PICTURE DATA: \n" ); document.write( "width = x-2(2)=x-4 inches \n" ); document.write( "length = 2x-1-2(2)= 2x-5 inches \n" ); document.write( "EQUATION: \n" ); document.write( "Picture area = length * width = 96 sq. in. \n" ); document.write( "(x-4)(2x-5)=96 \n" ); document.write( "2x^2-13x+20=96 \n" ); document.write( "2x^2-13x-76=0 \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Only x=10.22 is a usuable answer. \n" ); document.write( "So, dimensions of the picture are: \n" ); document.write( "width = x-2=8.22 inches \n" ); document.write( "length = 2x-5=15.44 inches \n" ); document.write( "cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |