document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=359939>Question 359939</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a retangle is 3 cm more than twice the width. if the perimeter is 84 cm find the dimensions </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #256823 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=256823\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 3 cm more than twice the width. if the perimeter is 84 cm find the dimensions<BR>\n" );
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document.write( "Let the width be \"w\".<BR>\n" );
document.write( "Then length = 2w+3.<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "P = 2(length + width)<BR>\n" );
document.write( "84 = 2(2w+3+w)<BR>\n" );
document.write( "42 = 3w+3<BR>\n" );
document.write( "39 = 3w<BR>\n" );
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document.write( "w = 13 cm (width)<BR>\n" );
document.write( "length = 2*13+3 = 29 cm<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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